Convergence or Divergence of Infinite Series: Methods and Examples

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SUMMARY

The forum discussion focuses on determining the convergence or divergence of the series Ʃ(1/(n*ln(n)^2 - n)) from n = 1 to infinity. Participants explored various methods including the Comparison Test and the Integral Test. The consensus is that the series can be analyzed effectively by starting from n = 3, as the initial terms do not affect convergence. Ultimately, using the Integral Test from n = 3 to infinity confirmed that the series converges.

PREREQUISITES
  • Understanding of series convergence tests, specifically the Comparison Test and Integral Test.
  • Familiarity with logarithmic functions and their properties.
  • Knowledge of p-Series and their convergence criteria.
  • Ability to analyze series behavior for large n.
NEXT STEPS
  • Study the Integral Test in detail, focusing on its application to series with logarithmic denominators.
  • Learn about the Comparison Test and Limit Comparison Test, including examples of their use.
  • Explore the properties of logarithmic functions in calculus, particularly in the context of series.
  • Practice problems involving convergence and divergence of series to reinforce understanding of the discussed methods.
USEFUL FOR

Students studying calculus, particularly those focusing on series convergence, as well as educators teaching these concepts. This discussion is also beneficial for anyone looking to deepen their understanding of convergence tests in mathematical analysis.

physicsernaw
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Homework Statement



Determine convergence or divergence using any method covered so far*:

Ʃ(1/(n*ln(n)^2 - n)) from n = 1 to infinity*The methods are the following:

- Dichotomy for positive series (if the partial sums are bounded above and the series is positive, the series converges)

- Integral Test

- Convergence of p-Series

- Comparison test

- Limit Comparison Test

Homework Equations



n/a

The Attempt at a Solution



The series is negative for n = 1 and 2, so I am left with Comparison test but I am having trouble determining what sequence to compare to. I am not "seeing" it.
 
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physicsernaw said:

Homework Statement



Determine convergence or divergence using any method covered so far*:

Ʃ(1/(n*ln(n)^2 - n)) from n = 1 to infinity

Is that denominator ##n\ln^2(n) -n## or ##n\ln (n^2)-n##?
*The methods are the following:

- Dichotomy for positive series (if the partial sums are bounded above and the series is positive, the series converges)

- Integral Test

- Convergence of p-Series

- Comparison test

- Limit Comparison Test

Homework Equations



n/a

The Attempt at a Solution



The series is negative for n = 1 and 2, so I am left with Comparison test but I am having trouble determining what sequence to compare to. I am not "seeing" it.

It doesn't matter if the first few terms of the series are negative. It is the tail end of the series that determines convergence or divergence. So don't rule out the other methods.
 
The denominator is the first one you posted, n*(ln(n))^2 - n.

In my book for the Limit Comparison Test it states "Let a[n] and b[n] be positive sequences." I assumed that "positive sequences" meant positive for all n [1, infinity). So it is really saying that if the sequence converges to a positive value or diverges "positively" than one can use the Limit Comp test on these sequences? Or am I still off base
 
physicsernaw said:
The denominator is the first one you posted, n*(ln(n))^2 - n.

In my book for the Limit Comparison Test it states "Let a[n] and b[n] be positive sequences." I assumed that "positive sequences" meant positive for all n [1, infinity). So it is really saying that if the sequence converges to a positive value or diverges "positively" than one can use the Limit Comp test on these sequences? Or am I still off base

If ##\sum_{n=3}^\infty a_n## converges or diverges, adding ##a_1+a_2## to it won't change the convergence or divergence. So analyze the sum from 3. I would suggest a combination of comparison and integral tests.
 
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Ahh I see thanks for clarifying. I will reattempt the problem.

EDIT: Got it by simply using integral test from n=3 to infinity. The integral converges so the series must as well. Thanks LCKurtz.
 
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