Conversion of cyclopropane to propene

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The discussion focuses on calculating the rate constant, k, for the conversion of cyclopropane to propene, a first-order reaction. The user initially applies the wrong formula, assuming the concentrations of cyclopropane and propene are the same, leading to an incorrect calculation of k as 0.0116. Another participant points out the misunderstanding, clarifying that the concentrations of the two compounds are different and should not be treated as equal. The correct answer for the rate constant is noted as 9.19 x 10^-4/s. The conversation highlights the importance of using the correct formula and understanding the relationship between reactants and products in chemical kinetics.
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Homework Statement




We examine the conversion of cyclopropane to propene, a first order process. If we begin with 0.0200 M cyclopropane and find that after 168 s the concentration of propene is 0.00286 M, what is the rate constant, k, at this temperature?



i used the forumula ln[A]/=-kt
=(ln 0.00286/0.02)/168=-k
therefore k=0.0116
however answer is 9.19 x 10-4/s

anyhelp would be good.
thanks
 
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geffman1 said:
We examine the conversion of cyclopropane to propene, a first order process. If we begin with 0.0200 M cyclopropane and find that after 168 s the concentration of propene is 0.00286 M, what is the rate constant, k, at this temperature?

Hi geffman1! :smile:

Aren't you using the formula for 0.0200 M cyclopropane and 0.00286 M cyclopropane? :redface:
 


hey, umm yep? I am confused
 
geffman1 said:
hey, umm yep? I am confused

Perhaps I've misunderstood your equation, but the question gives you the concentration of different compounds, and I think you've used an equation that asumes they're the same compound.
 

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