Convert 1.0L of Water to Pounds of Moon Rock

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To recover 1.0 L of water from moon rock, which contains 0.10 g of water per 100 g, the total mass of moon rock needed can be calculated using dimensional analysis. Given that the density of water is 1.0 g/mL, 1.0 L of water equals 1000 g. To find the mass of moon rock required, set up a conversion that accounts for the water content in moon rock. The calculations will show that a significant amount of moon rock must be processed to obtain the desired water volume. This problem highlights the importance of careful unit conversion and dimensional analysis in solving real-world resource recovery scenarios.
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Homework Statement


Moon rock contains 0.10 g of water in every 100 g of moon rock. What mass of moon rock, in pounds, would a moon base have to process to recover 1.0 L of water?


Homework Equations


Density of water is 1.0 g/mL


The Attempt at a Solution


I tried to convert the grams into pounds but that got me nowhere.
 
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1) Set up your dimensional analysis table
2) Plug your known values into 1st column
3) Set the rest of the table so like units on top and bottom cancel each other

remember that 1 L = 1000 mL
 
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