Convert 477 rev/min to Radians: Answer & Explanation

  • Thread starter Thread starter brncsfns5621
  • Start date Start date
  • Tags Tags
    Radians
AI Thread Summary
To convert 477 revolutions per minute (rev/min) to radians, the calculation involves multiplying by 2π, resulting in approximately 2997.07 radians. However, to express this in radians per second, it is necessary to divide by 60, since there are 60 seconds in a minute. The conversion from rev/min to radians/minute is valid, but the final result should be adjusted to radians/second for clarity. The discussion emphasizes the importance of understanding the units of angle/time in these conversions. Accurate conversion is crucial for applications requiring precise angular measurements.
brncsfns5621
Messages
22
Reaction score
0
If I was given 477 rev/min and I need to convert to radians, I would use:

477rev (2*pi radians/1 rev) = 2997.07 radians

Question is do I need to divide by 60 to get radians/second instead of minutes?
 
Physics news on Phys.org
brncsfns5621 said:
If I was given 477 rev/min and I need to convert to radians, I would use:

477rev (2*pi radians/1 rev) = 2997.07 radians

Question is do I need to divide by 60 to get radians/second instead of minutes?
rev/minute does not convert to radians. It converts to units of angle/time. So it converts to radians/minute (which you correctly show as 2\pi *477 = 2997 rad/min or 3000 rad/min. using 3 significant figures) or radians/sec. It is then a simple matter to convert your answer in radians/min to radians/sec.

AM
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top