Convert ppm to mg/L - Calculate Grams of A Needed

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To determine the amount of stable powder A needed for a concentration of 0.5 ppm of product C in 20 liters of water, it is established that 0.5 ppm equals 0.5 mg/L. This translates to needing 10 mg of C for the total volume, which means 100 mg of powder A is required since 10% of A becomes C. The calculation is confirmed as correct by multiple participants, despite some confusion regarding the question's wording. The discussion highlights the relationship between the mass of A and the resulting product C.
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Homework Statement


A is a stable powder
B is water
C is the product of the powder being in contact with water.

A is soluble in substance B and for every gram of A 10% is C.

For a concentration of 0.5ppm of C in twenty liters of water how many grams of A do you need?


The Attempt at a Solution


I went on the assumption that ppm=mg/l.
So 0.5ppm=0.5mg/l, and I would need 10mg for the twenty liters
Which means that I would need 100mg of A.

Is this correct?
 
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Cypher49 said:
I would need 100mg of A.

Is this correct?

That would be my answer as well, although I find the wording of the question confusing.
 
Thanks for the confirmation, I'm just replying to say that 100mg was indeed the correct answer.

If you don't mind me asking, how did the wording confuse you?
 
If 0.1g of A reacted with water, what is mass of the product? Again 0.1g? Not impossible, but counterintuitive, at least to me.
 
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