f(x,y) = sqrt(x^2+y^2)
over triangle with vertices (0,0) (0,sqrt2) (sqrt 2, sqrt 2)
x= rcosO, y = rsinO
The Attempt at a Solution
im supposed to use a double integral converted to polar coordinates,
so i used the bounds int. 0 to pi/4 int. 0 to sqrt 2 sec (r^2) drdO
are these the correct bounds? because i cant seem to find the answer.