Convert triangle vertices to double integral polar coordiantes

  • Thread starter ramses07
  • Start date
  • #1
11
0

Homework Statement



integrate

f(x,y) = sqrt(x^2+y^2)

over triangle with vertices (0,0) (0,sqrt2) (sqrt 2, sqrt 2)

Homework Equations



x= rcosO, y = rsinO

x^2+y^2=r^2

The Attempt at a Solution



im supposed to use a double integral converted to polar coordinates,
so i used the bounds int. 0 to pi/4 int. 0 to sqrt 2 sec (r^2) drdO

are these the correct bounds? because i cant seem to find the answer.
 

Answers and Replies

  • #2
2,552
3
I think your bounds for theta should be pi/4 to pi/2
 
  • #3
11
0
how do you know what the bounds are?
 
  • #4
2,552
3
because the line y=x cuts it at a 45 degree angle and x=0 goes up to 90 so it goes from 45 to 90
like cutting a wedge out of a circle , but the radius is different , i think your bounds for the radius are correct.
 

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