Converting Analog Signals to Digital: A 2-bit A/D System

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The discussion focuses on converting analog signals to digital using a 2-bit A/D system, which can represent four distinct levels. The original analog signal levels range from 0 to 10, divided into four intervals of 2.5 each. The proposed assignments for the digital words are analyzed, leading to the conclusion that the correct mapping would assign 00 to 0-2.5, 01 to 2.5-5, 10 to 5-7.5, and 11 to 7.5-10. After evaluating the options, the consensus is that the answer is A, with the specific assignments being a=00, b=01, c=11, d=10, and e=01. This illustrates the importance of understanding digitization rules in A/D conversion.
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Obtain the digital words corresponding to the indicated analog signal levels, a through j, as shown in Figure P8.38, that would be assigned by an A/D system with 2 bits.

http://img256.imageshack.us/f/eehmrw1.png/

a. None of the above
b. a=11, b=01,c=10,d=01, and e=01
c. a=11,b=10,c=01,d=01, and e=10
d. a=00,b=10,c=01,d=10, and e=10


I understand what the position and weight of the digit imply but for some reason no matter how I look at this problem I cannot seem to make sense of it.

Any help would be greatly appreciated.
 
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I suppose it depends upon what the rules you're using for digitization are, but given that two bits can only result in four distinct digital signal levels, and given that the original analog signal levels range between 0 and 15, it would seem to make sense to divide that range into four intervals -- everything in the lowest interval gets assigned 00, et cetera.
 
Okay, that makes sense.

Now if I was using signal levels a through e only:

~The range would be from 0 to 10 and have 4 zones.
~Thus 10/4 = 2.5

~00 is 0-2.5
~01 is 2.5-5
~10 is 5-7.5
~11 is 7.5-10

If that is all correct then the answer would indeed be A because:

a=00
b=01
c=11
d=10
e=01
 
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