Converting Coulombs->Charges and vice versa

Thread starter scorchy11
Start date Feb 4, 2010

AI Thread Summary

To convert Coulombs to charges, divide the number of Coulombs by the elementary charge, approximately 1.602 x 10^-19 Coulombs per electron. Conversely, to convert charges to Coulombs, multiply the number of charges by the elementary charge value. A Coulomb is equivalent to about 6.242 x 10^18 electron charges. Understanding this relationship is crucial for solving problems related to electric charge in physics. Mastering these conversions is essential for success in upcoming tests.

Feb 4, 2010

scorchy11

Hello all,

Can anyone help me learn how to convert Coulombs to Charges and vice versa (Charges to Coulombs).

My Prof has abadoned the class and we have a term test on Monday.

Thank you for your help.

Physics news on Phys.org

Feb 4, 2010

rock.freak667

Homework Helper

What do you mean to 'charges'? Charge is measured in Coulombs.

Feb 4, 2010

Matterwave

Science Advisor

Homework Helper

Gold Member

A coulomb consists of ~6.242×10^18 electron charges (aka elementary charge units). Therefore, an electron's charge is 1.602*10^-19 Coulombs.

Thread 'I've come across another fluid pressure problem I don't understand'

Neglect gravity other than that of water; neglect friction. F1=ρgsh=1000*10*1*(1+4)=50000 N; F1=ρgsh=1000*10*0.1*4=4000 N; F3=50000-4000=46000 N?

View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

View full post »

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

View full post »