Converting degree into variable 'x'

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The discussion centers on converting the result of an integral, specifically 1/2¤ - 1/2sin2¤ + c, into a format using the variable x. The user successfully converted 1/2¤ to 1/2arcsinx but struggled with 1/2sin2¤, which should align with the textbook's answer of 1/2x(sqrt1-x²). The relationship sin2x = 2sinx.cosx is mentioned as relevant to the conversion. The user seeks clarification on how to complete the conversion accurately. The thread highlights the challenges of integrating trigonometric functions and converting between variable formats.
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Homework Statement


After integrating x²/(sqrt1-x²) using the triangle method and thereby substituting sin¤ for x, I ended up with the result 1/2¤-1/2sin2¤+c. For my answer toge complete, I must have the ¤ in x format. I managed to convert the 1/2¤, which is simply 1/2arcsinx but I couldn't for 1/2sin2¤, my answer did not agree with the textbook's which read 1/2x(sqrt1-x²)...

My computer won't read latex at the moment so please excuse the amateur notation. Thank you.

Homework Equations


I think I covered it all above!
 
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sin2x = 2sinx.cosx
 
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