Converting Half Life to Becquerels

  • Thread starter Thread starter schumi
  • Start date Start date
  • Tags Tags
    Half life Life
schumi
Messages
6
Reaction score
0
Can you convert Half Life into Becquerels? How?
 
Physics news on Phys.org
They are different kinds of units. Half-life is defined for a specific radionuclide, independent of how much. Becquerel depends on the total quantity of the material.
 
One Becquerel is one nuclear decay per second. The half-life t½ is the time it takes half of the nuclei to decay. Related to t½ is the decay constant: t½ = ln(2)/λ. The significance of the decay constant λ is that it is the fractional rate per second at which nuclei are decaying:

dN/dt = - λ N

So if you multiply λ by the number of nuclei present, N, you'll get the number of decays per second, which is Becquerels.
 
Thank you, that made it clear.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top