Attached is a graph that has the coolant heat flow rate divided by brake HP. I took the revs that make the most power (from dyno test) and got a value (0.95). It depends on the engine type as seen on the right corner.
Once you have the value place your engines brake Power (in KW) and compute the heat flow needed to remove (Q dot = value X power [KW]).
Now let's make a few assumptions:
The water temp entering the radiator : 100 degrees C.
The water temp exiting the radiator : 80 degrees C.
The delta= 20 C.
from the famous equation: Qdot=mDot X Cp X delta T
You can isolate the mdot and calculate it.
The graph is from an auto engineering book.. I don't remember which one.