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Cooper Pair Wave Function

  1. Oct 29, 2011 #1


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    Can anyone help me, I am some what unclear on the reason why "conventional" superconductors have cooper pairs only in the singlet state. Is it something to do with the expectation values given for the separate states calculated from their spacial and spin wave functions? For example does the singlet state with an even spacial wave function and an odd spin wave function give a lower Energy eigenvalue when operated on using the Hamiltonian compared to the triplet (spin anti parallel) state?

    Does BCS theory only predict singlet cooper pairs or just state that it is the more favorable ?

    I know that cooper pairs have a zero center of mass momentum and anti parallel spins. Is the the anti parallel spin due to the Pauli principle (would that matter as the cooper pair is essentially a composite boson?) or due to a lower expectation value given by the Hamiltonian?
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  3. Oct 29, 2011 #2


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    I might be wrong here, but I don't think there is a "general" reason. You canuse whatever symmetry you want in the BCS theory, it just happens to be that s-wave is the most common type in conventional superconductors, but this is presumably due to the materials themselves and not due to the theory as such.
    Note that for example P-wave superconductors etc are -usually- refered to as conventional and are described by the BCS theory.
  4. Oct 29, 2011 #3


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    Surely if the majority of superconductors only have a singlet amplitude, it must be in general more favorable to have a singlet state rather than a spin anti parallel or spin parallel triplet.
  5. Oct 30, 2011 #4


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    But in the ruthenates, it is NOT favorable to have a single state!

    Again, a lot of factors influence the ground state symmetry. So it depends on what you mean by "favorable". It is more favorable to have more Type II superconductors?

  6. Oct 30, 2011 #5


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    Is there a dominant factor that influences the singlet state in most superconductors?
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