Coordinate charts to cover a circle?

pivoxa15
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4 charts seem to cover it. BUt only 2 will do for a minimal number?

Just like 2 charts will do to cover a sphere? Even though there are 6 all together.
 
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I'm not sure why you add that "6 altogether". What 6 charts are you talking about? Yes, of course, two charts will cover a circle. Choose one as (-\alpha < \theta < \pi+ \alpha) and the other (\pi-\alpha < \theta < 2\p+ \alpha ) where \alpha is some small number.
 
i think we are agreed that you can cover a circle with different number of charts but 2 is the minimal number
what you ask is possibly a special way of finding charts.
I guess the method you use is for circle first taking upper half of circle(of course as an open set the end points are not included) than letting any point (x,y) on circle to go (x,0) for example.this gives first chart ,doing same for the lower half gives second one .and for each remaining two points (end points of the half circle) we take a open nhd and suitable hom. So you obtain 4 charts
same method gives for sphere 6 charts but 2 is enough (which is found by different methods.the latter is found by stereographic projection usually)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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