iRaid
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Homework Statement
[itex]\int cos^{2}x dx[/itex]
I know that
[itex]cos^{2}x = \frac{1+cos2x}{2}[/itex]
but I don't see how that helps me.
Can someone help walk me through it..
iRaid said:u=2x du=(1/2)dx
(1/2)∫cosudu
=(1/4)sin2x
So then..
x/2 + (1/4)sin2x
but that's not the answer..
Dick said:I think it is the correct answer. You should probably put a +C on it. Is that the problem?