- #1
jackson_sun
- 11
- 0
I have been asked to differentiate cos x and six...the maclaurin series versions...
I have done the general and specific terms as shown below.
Im not sure if these are correct?
thanks
General Terms
cos x = ∑ (-1)n (x^(2n) / (2n)!)
COS x = ∑ (-1)n (x^(2n+1)/ (2n +1) / (2n)!)
sin x = ∑ (-1)n (x^(2n+1) / (2n+1)!)
‘sin x = ∑ (-1)n (((2n+1) x^(2n))/ (2n+1)!)
Specific Terms
sin x = x – (x^3 / 3!) + (x^5 / 5!) – (x^7 / 7!) + (x^9 / 9!) - …
‘sin x = 1 – (3x^2 / 3!) + (5x^4 / 5!) - (7x^6 / 7!) + (9x^8 / 9!) - …
cos x = 1 – (x^2 / 2!) + (x^4 / 4!) – (x^6 / 6!) + (x^8 / 8!) - …
COS x = x – (x^3 / 3 / 2!) + (x^5 / 5 / 4!) – (x^7 / 7 / 6!) + (x^9 / 9 / 8!) - …
thanks
I have done the general and specific terms as shown below.
Im not sure if these are correct?
thanks
General Terms
cos x = ∑ (-1)n (x^(2n) / (2n)!)
COS x = ∑ (-1)n (x^(2n+1)/ (2n +1) / (2n)!)
sin x = ∑ (-1)n (x^(2n+1) / (2n+1)!)
‘sin x = ∑ (-1)n (((2n+1) x^(2n))/ (2n+1)!)
Specific Terms
sin x = x – (x^3 / 3!) + (x^5 / 5!) – (x^7 / 7!) + (x^9 / 9!) - …
‘sin x = 1 – (3x^2 / 3!) + (5x^4 / 5!) - (7x^6 / 7!) + (9x^8 / 9!) - …
cos x = 1 – (x^2 / 2!) + (x^4 / 4!) – (x^6 / 6!) + (x^8 / 8!) - …
COS x = x – (x^3 / 3 / 2!) + (x^5 / 5 / 4!) – (x^7 / 7 / 6!) + (x^9 / 9 / 8!) - …
thanks