Cosine for synchronous demodulation

AI Thread Summary
Synchronous demodulation involves multiplying the modulated signal x(t) by the carrier signal xc(t) to recover the original modulation xm(t). The parameters given include a modulation index m of 0.8, a carrier frequency fc of 2000 Hz, and a modulation frequency fm of 200 Hz. Participants in the discussion express confusion about the initial steps, with some suggesting that the goal is to recover xm(t) by using xc(t) in the multiplication process. There is a consensus that simply dividing x(t) by (1+m*xm(t)) would not be appropriate, as it assumes perfect knowledge of the modulation. The ultimate aim is to accurately retrieve the original signal xm(t) through the correct application of synchronous demodulation techniques.
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Homework Statement



Synchronous demodulate x(t).

Homework Equations



xc(t) = cos(2pi*fc*t), fc is the carrier frequency
xm(t) = cos(2pi*fm*t), fm is the modulation frequency

x(t) = xc(t)*(1+m*xm(t)), m is the modulation index
m = .8
fc = 2000 hz
fm = 200 hz

The Attempt at a Solution



I really don't even know where to start. I know synchronous demodulation means I multiply x(t) by a function, but how do I come up with that function? I realize that I could divide x(t) by (1+m*xm(t)), but that doesn't seem to be what the problem is asking.
 
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ƒ(x) said:
xc(t) = cos(2pi*fc*t), fc is the carrier frequency
xm(t) = cos(2pi*fm*t), fm is the modulation frequency

x(t) = xc(t)*(1+m*xm(t)), m is the modulation index
m = .8
fc = 2000 hz
fm = 200 hz

The Attempt at a Solution



I really don't even know where to start. I know synchronous demodulation means I multiply x(t) by a function, but how do I come up with that function? I realize that I could divide x(t) by (1+m*xm(t)), but that doesn't seem to be what the problem is asking.
No, that would involve the receiver being able to predict the modulation perfectly, so there would be little point in sending it in the first place.

I don't know where to start, either. But isn't synchronous something about multiplying by the carrier? So why not try multiplying x(t) by xc(t) and see what you can get from that? The whole idea is to recover xm(t), presumably?
 
NascentOxygen said:
No, that would involve the receiver being able to predict the modulation perfectly, so there would be little point in sending it in the first place.

I don't know where to start, either. But isn't synchronous something about multiplying by the carrier? So why not try multiplying x(t) by xc(t) and see what you can get from that? The whole idea is to recover xm(t), presumably?

I think I'm supposed to do x(t) * xc(t) and then the next step is to use a step function of sorts. The point is to recover xc(t) since that's the original signal.

Edit: My mistake, I was misreading the problem. You're correct. I'm supposed to recover xm(t).
 
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