Could I get a second pair of eyes on this?

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The discussion revolves around verifying a solution to a physics problem involving forces at a hinge. The user questioned whether the vertical component of the hinge's force equals the sum of vertical forces acting in the negative direction. Responses clarified that the tension's vertical component must also be included in the calculations for static equilibrium. The user expressed gratitude for the guidance received, indicating a better understanding of the problem. Overall, the interaction highlights the importance of considering all forces in equilibrium problems.
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OP warned about not using the homework template
1. Link to problem and the answer I got - https://ibb.co/ncGfDA

2. I got an answer, but I was wondering if this is correct or not? Am I correct to say (in part c) that the vertical component of the hinge's force will be equal to the sum of the vertical forces being exerted in the negative direction?


3. I attempted my answer (hopefully finished) in the link above
 
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dangerboyy said:
Link to full question and my answer at the bottom of text

I got an answer, but I was wondering if this is correct or not? Am I correct to say (in part c) that the vertical component of the hinge's force will be equal to the sum of the vertical forces being exerted in the negative direction?


https://ibb.co/ncGfDA
Hello @dangerboyy . :welcome:

Please use the homework template provided when you open a Thread.

For reference:
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SammyS said:
Hello @dangerboyy . :welcome:

Please use the homework template provided when you open a Thread.
Sorry, I'll keep this in mind. I'm a newby here who didn't pay enough attention to how to do the template, simply hoping my text would suffice.

edit - post is now in the proper template i believe
 

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dangerboyy said:

Am I correct to say (in part c) that the vertical component of the hinge's force will be equal to the sum of the vertical forces being exerted in the negative direction?
Not quite. Wouldn't you need to include the vertical component of FT in your calculation of (FH)y?
 
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TSny said:
Not quite. Wouldn't you need to include the vertical component of FT in your calculation of (FH)y?
That's what I was thinking, but I wasn't exactly sure how to get an answer if I did so. May I request guidance?
 
The system is in static equilibrium. So, what can you say about ΣFx and ΣFy?
 
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TSny said:
The system is in static equilibrium. So, what can you say about ΣFx and ΣFy?
Well, ΣFx and ΣFy must both equal 0 in static equilibrium. How could I separate Fy in the positive direction among the cord and hinge?

edit - a light bulb turned on in my brain - Could I find Fy of the cord, then subtract from the total Fy in the positive direction to find that of the hinge?
 
dangerboyy said:
That's what I was thinking, but I wasn't exactly sure how to get an answer if I did so. May I request guidance?

You’ve done everything correctly except when you balanced the vertical forces you forgot to include the tension. In exactly the same way you included Ft cos(30) in the horizontal forces add the vertical component into to equation with the vertical forces. It’s just one more term, and you already know the value.
 
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Cutter Ketch said:
You’ve done everything correctly except when you balanced the vertical forces you forgot to include the tension. In exactly the same way you included Ft cos(30) in the horizontal forces add the vertical component into to equation with the vertical forces. It’s just one more term, and you already know the value.
Thanks! I believe I have this well understood now. Thanks to all others who helped me look past my stupidity as well. I'm brand new to this community, and this was a great first experience. Thanks
 
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dangerboyy said:
Thanks! I believe I have this well understood now. Thanks to all others who helped me look past my stupidity as well. I'm brand new to this community, and this was a great first experience. Thanks
OK. Great! Welcome to PhysicsForums.
 
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