Could someone check if this is right soon.

[Ion1776]

Could someone please check if this is right soon. please

What would the bank angle be for a circular racetrack with radius 120 m so that a car can go around the curve safely at a maximum of 25 m/s, without the help of frictional force to keep it on the road?

(25^2)/(120)/(9.80)=.53146

ArcSin(.53146)=32.1 Degrees

is this right, could someone check it for me

Thanks

 

[Delphi51]

I would have used arctan rather than arcsin. Maybe you should take time to draw the vector diagram to be sure.

 

[Ion1776]

ArcTan doesn't give you the right answer. Could you help me at all, more in depthly.

 

[Delphi51]

 

[Ion1776]

So is it

Arctan(5.208/9.81)=27.96

 

[Delphi51]

Yes, that's what I got.

 

[Ion1776]

One more thing, how did you get the 5.208

 

[Delphi51]

Fc = mv^2/R = m*25^2/120 = 5.208*m
This is the centripetal or centrifugal force. From the point of view of the outside world, the force is inward needed to hold the car in circular motion. From the point of view of the car in circular motion, the force is outward, tending to push it out of circular motion into straight line motion.