Ok, I am in an intro to physics, so it is all trig based. But I just need to know if I did these vector problems right. an object in equilibrium has 3 forces exerted on it. one at 90 degress is 33N, one at 60 degrees is 44N. Find the third. Using the sine and cosine of those vectors, i got the thrid force to be 74.3N at 253 degrees. Is that right? ANd the other one is: five forces act on an object, the first is 60N at 90 degrees, the second is 40N at o degrees, the third is 80N at 270 degrees, te fourth is 50N at 60 degrees, and the fifth is 40N at 180 degrees. whats the sixth force that puts the object in equilibrium? I know that the 2 40N forces cancel, so i just found the vertical and horizontal force of the other three forces. Then after using more sin and cos laws, and Fnet6^2 =Fnetx^2 + Fnety^2 I got the force should be 33.97N, and using tanget, it should be at 43 degrees.