Could someone please explain this 4-vector/tensor notation?

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The discussion focuses on understanding the notation and implications of 4-vector and tensor equations in electromagnetism and relativistic quantum mechanics. The equation for the antisymmetric field tensor, F_{\mu \nu} = ∂A_\nu/∂x^\mu - ∂A_\mu/∂x^\nu, involves taking partial derivatives of the 4-vector potential A with respect to spacetime coordinates, indicating how the field varies in space and time. Participants clarify that when operating on derivatives, such as ∂_\mu[∂_\nuΨ(x^\mu)], the order of differentiation does not change the result, and summation over repeated indices is implied. The conversation emphasizes the importance of distinct dummy indices to avoid confusion in tensor notation. Overall, the thread provides insights into the complexities of tensor calculus in physics.
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If you can answer any of the questions below, your help will be greatly appreciated.

There's an equation from E&M (I believe the definition of the antisymmetric field tensor) that reads:

<br /> F_{\mu \nu} = \frac{\partial A_\nu}{\partial x^\mu} - \frac{\partial A_\mu}{\partial x^\nu},<br />

where (of course) A is the 4-vector potential. I have no idea how to parse this equation...what's going on with taking the partial of A_\nu with respect to x^\mu? What's this notation describing, or telling me to do? I just don't see it.

Also (and this pertains to relativistic quantum mechanics), what's meant by something like

<br /> \partial_\mu [\partial_\nu \Psi(x^\mu)],<br />

where (of course) \Psi(x^\mu) is the wave function? I.e., what does it mean to operate on \partial_\nu of something with \partial_\mu? Particularly when that something I'm operating on is a function of x^\mu? (By the way: In case the notation is unfamiliar to you, \partial^\mu = \partial / \partial x_\mu.) Does that turn into something? Can I compactify that? Or do I just have to leave it as \partial_\mu [\partial_\nu \Psi(x^\mu)]? Also, would I get an equivalent expression if I interchanged the order of \partial_\mu and \partial_\nu; i.e., if I tried to evaluate \partial_\nu [\partial_\mu \Psi(x^\mu)]? Or would I get something quite different?

Does all of this boil down to "we need two distinct dummy indices, \mu and \nu, to indicate that there shouldn't be any summation going on?"

(P.S. - I would like to thank David J. Griffiths for getting me into the habit of italicizing words I want to emphasize.)
 
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AxiomOfChoice said:
<br /> F_{\mu \nu} = \frac{\partial A_\nu}{\partial x^\mu} - \frac{\partial A_\mu}{\partial x^\nu},<br />

where (of course) A is the 4-vector potential. I have no idea how to parse this equation...what's going on with taking the partial of A_\nu with respect to x^\mu?

Given two four vectors, one for the field, and one for the spacetime
position

<br /> \vec{A} = (A_0, -A_1, -A_2, -A_3)<br />
<br /> \vec{x} = (x^0, x^1, x^2, x^3) = (ct, x, y, z)<br />

This says that there's 16 scalar quantities that can be calculated by
taking derivatives. Two examples are:

<br /> F_{23} = <br /> \frac{\partial A_3}{\partial x^2} - \frac{\partial A_2}{\partial x^3} = <br /> \frac{\partial A_3}{\partial y} - \frac{\partial A_2}{\partial z}<br />

<br /> F_{33} = <br /> \frac{\partial A_3}{\partial x^3} - \frac{\partial A_3}{\partial x^3} = 0<br />

For your other question, I'd assume summation over \mu is implied.
 
Thanks a lot for your help!

What if I confront something like

<br /> \frac{\partial F^{\mu \nu}}{\partial x^\nu} = \partial_\nu F^{\mu \nu}?<br />

Does that imply a sum over \nu?
 
Yes, if an index is repeated as an upper index and a lower index, it implies a sum over that index.
 

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