Could the Moon's Shape Explain Why We Only See One Side?

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The discussion centers on the phenomenon of the Moon being tidally locked to Earth, leading to the same side always facing us. It is clarified that this is not a coincidence or due to one side being heavier, but rather a result of gravitational forces and the Moon's non-spherical shape. The Moon's center of gravity being offset is explained as a misconception; instead, its ellipsoidal shape and the gravitational pull from Earth create this orientation. The complexities of tidal locking involve the Moon's quadrupole moment and mass distribution. Overall, the consensus emphasizes that tidal forces, not mass distribution, are responsible for the Moon's consistent orientation towards Earth.
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Here's another observation of nature

"I don't think the moon's spin cancels it's orbit (causing the same side to face us) by tidal forces or by accident. That would be one big coincidence. I think that the moon's center of gravity is offset from it's center point along it's diameter. So "The heavy side faces us"

Is this mentioned somewhere? I couldn't find it. If not does anyone agree that this could be possible?" or am I again "out of my mind"?
 
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No, it's not by "accident" nor does it follow that one side must be heavier than the other- the moon is "tidally locked" to the earth. Why do you say you don't think it could be caused by tidal forces? That's certainly not a coincidence!

Do you understand what is meant by "tidally locked"? It has nothing to do with the tides on earth- more to do with "tides" on the moon!

Here is a good explanation:
http://en.wikipedia.org/wiki/Tidal_locking
 
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It is not just the heavier side facing us.
It's more complicated than that. It has to do with the quadrupole moment of the moon due to non-spherically symmetric distribution of it's mass.
 
Meir Achuz said:
It is not just the heavier side facing us.
It's more complicated than that. It has to do with the quadrupole moment of the moon due to non-spherically symmetric distribution of it's mass.

non-spherically symmetric distribution of it's mass? Doesn't that mean it's center of gravity is offset from it's center of mass?
 
No, the moon is basically football-shaped (an ellipsoid) and since the force of Earth's gravity on the near-side is greater than that on the far-side (because of the distance), it stays in that orientation. The Earth technically has an ellipsoid component as well (same reason - the tides), but it is very small compared to Earth's rotation-induced oblateness.

The link you provided before that mentioned the crust being thicker on the other side doesn't mean that side is heavier - the crust is thin and light.
 
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Assume that this is a case where by sheer coincidence, two sources of coherent single-frequency EM wave pulses with equal duration are both fired in opposing directions, with both carrying the same frequency and amplitude and orientation. These two waves meet head-on while moving in opposing directions, and their phases are precisely offset by 180 degrees so that each trough of one wave meets with the crest of the other. This should be true for both the electric and magnetic components of...

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