Coulombic force of repulsion/attraction between ions

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Discussion Overview

The discussion revolves around calculating the Coulombic forces of attraction and repulsion between ions in calcium oxide (CaO), specifically focusing on the ionic radii of Ca2+ and O2- ions and the implications of the NaCl-type crystal structure. Participants explore theoretical calculations, the significance of crystal structure, and the nature of ionic interactions.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Participants calculate the Coulomb force of attraction between Ca2+ and O2- ions using the formula provided, with one participant suggesting a calculated value of 1.63x10-8 N.
  • Some participants question the significance of the NaCl-type structure, noting that it helps determine the distance between like ions, which is crucial for calculations.
  • There is a discussion about whether the attractive force can be derived from the repulsive force by flipping the sign, with some participants asserting that the Coulomb force can be either attractive or repulsive depending on the signs of the charges involved.
  • One participant expresses uncertainty about the arrangement of ions within the crystal lattice and how that affects calculations, suggesting that visual aids might help clarify the spatial relationships.
  • Another participant emphasizes the complexity of real bonding, indicating that it cannot be reduced to simple calculations of attractive and repulsive forces due to quantum mechanical factors.

Areas of Agreement / Disagreement

Participants generally agree on the use of the Coulomb force formula but express differing views on the implications of the NaCl-type structure and the nature of ionic interactions. The discussion remains unresolved regarding the exact arrangement of ions within the crystal lattice and its impact on calculations.

Contextual Notes

Participants note that the calculations depend on the assumptions about the ionic arrangement and the definitions of the forces involved. There is also mention of the need for clarity regarding the positions of ions in the crystal lattice, which may not have been fully covered in prior learning.

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Homework Statement


The ionic radius of the Ca2+ ion is 0.106nm. The ionic radius of the O2- ion is 0.132nm.
a.Calculate the coulomb force of repulsion between nearest neighbor O2- ions in CaO (which has the NaCl-type structure).
b. Calculate the colombia force of repulsion between nearest neighbor Ca2+ ions in CaO (which has the NaCl-type structure).
c. Calculate the coulomb force of attraction between Ca2+ ions and O2- ions in CaO (which has the NaCl-type structure).

Homework Equations


Fc=-k(Z1q1)(Z2q2)/a2
k=constant=9x109Nm2/C2
Z represents the valences of the two ions
a is the interatomic spacing
q is the magnitude of charge of the electron

The Attempt at a Solution


I believe I can do c:
a=0.106nm+0.132nm=0.238nm
Fc= - k(+2 x 1.602x10-19c)(-2 x 1.602x10-19c)/(0.238x10^-9m)2 = 1.63x10-8 N

I have a couple questions:
1. What is the significance of the problem telling us "which has the NaCl-type structure" in each part? Is this just telling us that CaO is bonded ionically?
2. I know that repulsive force(Fr)+attractive force(Fc)=0, therefore Fr=-Fc
So does this mean that I can calculate the attractive force between two nearest neighbor O2- ions, then flip the sign and call it the repulsive force?
3. If this is true then are we saying there is an attractive force between two negatively charged things (O2-'s? I realize within CaO the Ca2+ and O2- have an attractive and repulsive force which equals zero (that is why they are held together within the molecule).

I guess I want to know if the same process can be used for part C on part A and B, and if so why?

Thanks!
 
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cookiemnstr510510 said:
1. What is the significance of the problem telling us "which has the NaCl-type structure" in each part? Is this just telling us that CaO is bonded ionically?
This is necessary to figure out the distance between two like ions. NaCl has a cubic structure. If the crystal structure had been different, then the distance between say two O2- ions would not be the same.

cookiemnstr510510 said:
2. I know that repulsive force(Fr)+attractive force(Fc)=0, therefore Fr=-Fc
So does this mean that I can calculate the attractive force between two nearest neighbor O2- ions, then flip the sign and call it the repulsive force?
Fc is the Coulomb force, which is not necessarily an attractive force. Whether it will be attractive or repulsive depends on the sign of Fc.

cookiemnstr510510 said:
3. If this is true then are we saying there is an attractive force between two negatively charged things (O2-'s? I realize within CaO the Ca2+ and O2- have an attractive and repulsive force which equals zero (that is why they are held together within the molecule).
You have to be careful here, as real bonding is much more complicated than simply calculating attractive and repulsive forces, since it is quantum mechanical in nature.
 
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DrClaude said:
This is necessary to figure out the distance between two like ions. NaCl has a cubic structure. If the crystal structure had been different, then the distance between say two O2- ions would not be the same.Fc is the Coulomb force, which is not necessarily an attractive force. Whether it will be attractive or repulsive depends on the sign of Fc.You have to be careful here, as real bonding is much more complicated than simply calculating attractive and repulsive forces, since it is quantum mechanical in nature.
thank you! Will respond tomorrow when I have more time to read it over
 
Okay, I am gathering from what you are saying is that Fc could either be a coulombic force of attraction or repulsion.
In the case of O2-, a=0.132nm + 0.132nm=0.264nm=0.264x10-9m
Z1=-2, Z2=-2, q=1.602x10-19C
Fc=-(9x109Nm2/C2)((-2)(1.602x10-19C))((-2)(1.602x10-19C))/((0.264x10-9m)2)= -1.33x10-8N would be the repulsive force between two nearest neighbor O2- ions? Not asking to check my math, just wondering if this is the correct method to obtain the answer for the question.
Thanks!
 
cookiemnstr510510 said:
Not asking to check my math, just wondering if this is the correct method to obtain the answer for the question.
Well, yes and no. Actually, I'm not sure how to disentangle the two here. The method is correct in that you are using the right formula for ##F_c##, but incorrect in that you are not thinking properly about where the ions are sitting. Making a drawing might help.
 
DrClaude said:
Well, yes and no. Actually, I'm not sure how to disentangle the two here. The method is correct in that you are using the right formula for ##F_c##, but incorrect in that you are not thinking properly about where the ions are sitting. Making a drawing might help.
hmm. okay. Does this have to do with the crystal lattice of CaO? If so since it is NaCl type it would also be FCC. In that case I know what FCC unit cells look like. But I am not sure where two nearest neighbor O2-'s would lie. I haven't been taught how an actual compound would arrange itself within a unit cell.
 
cookiemnstr510510 said:
hmm. okay. Does this have to do with the crystal lattice of CaO? If so since it is NaCl type it would also be FCC. In that case I know what FCC unit cells look like. But I am not sure where two nearest neighbor O2-'s would lie. I haven't been taught how an actual compound would arrange itself within a unit cell.
Be careful: if you take only one type of ion, then the structure is FCC, but both ions together form a simple cubic structure. The link I gave in post #2 shows a picture of the structure, so you can use this to figure out the distance between two like ions.
 
ahhhh okay, this makes much more sense! thank you Dr. Claude
 

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