Counter emf generated in a motor at full speed

AI Thread Summary
The discussion centers on calculating the counter electromotive force (emf) generated by an electric motor at full speed. Initially, the motor draws 20.0 A with a resistance of 5.0 ohms, resulting in a voltage of 100 V. At full speed, the current drops to 4.4 A, leading to a voltage of 22 V. The counter emf is calculated by subtracting the voltage at full speed from the initial voltage, yielding 78 V. The participant questions whether they are missing a concept related to "change," but believes their calculations are correct.
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Homework Statement


An electric motor draws 20.0 A of current when first switched on. The motors windings have a resistance of 5.0 ohm. Once the motor is up to full speed it draws only 4.4 A of current. Calculate the counter emf generated in the motor at full speed

Homework Equations


I = V/R
V=IR

The Attempt at a Solution


R = 5.0 ohm
A1 = 20.0 A
A2= 4.4 A n

1. (20A)(5.0ohm) = 100 V

2. (4.4A)(5.0ohm) = 22V

3. 100V - 22V = 78V

Im told I am missing some "change", however I think this is correct, it is change in voltage?
 
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