Couple of Physics Questions

  • Thread starter Matthew
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  • #1
Matthew
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Hey can someone help me out with one or both of these questions?

1. A dog sees a flowerpot sail up and then back down a window (height of window is 1.77m). If the total time the pot is in sight for 1.0 s, find the height above the top of the window to which the pot rises.


2. A runner hopes to complete a 10-km run in 30.0 min. After exactly 27.0 min there is still 1100 m to go. The runner must then accelerate at 0.20 m/s^2 for how many seconds in order to exactly achieve his desired time?

Thanks in advance
 

Answers and Replies

  • #2
Chi Meson
Science Advisor
Homework Helper
1,874
10
Here's some clues for question 1:

This problem is a "two-parter" . The magnitudes of the velocities are the same as the pot passes the top of the window on the way up and one the way down. Ditto for the velocities at the bottom. THis means that you can cut the time given in half and solve for a single "free-fall" problem using displacement, time and acceleration as your known variables, and solve for the velocity at the top of the window. THen do the second part.
 

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