Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Critical angle and area

  1. Aug 24, 2011 #1
    1. The problem statement, all variables and given/known data
    calculate the critical angle for light at a water (n=1.33) and air (n=1) interface.
    if a fish is 2m below the surface of the water , calculate the area at the surface through which the fish can viw the world above the water.

    2. Relevant equations

    none given

    3. The attempt at a solution

    critical angle = sin theta c= n2/n1 = 48.75 deg

    area of surface=

    using basic trig find out all the sides and angles of triangle ..
    then area of tribgle is .5*2.28*2 = 2.28 m^2

    am i right in all this??
  2. jcsd
  3. Aug 24, 2011 #2


    User Avatar
    Homework Helper

    the Area on the SURFACE that the fish sees thru ...
    it looks like a circular disk of bright blue sky directly above the fish ... out to 48deg.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook