- #1
Barley
- 17
- 0
I know that if the curl is zero then the Force is conservative, and that the curl is the cross product of the gradient and the Force function. What I'm having, I think, is a math problem;
Probably not able to get the partial derivatives of the function right...
Ok, first off, have a Force that is a function of position: F = ax, where a is a constant--I know the solution to the curl is a in the direction of z; not conservative. But, when I set up my cross product matrix I have for the partials in the z and z direction as zero, and the Fy and Fz too. Now this leaves me with only a and ax in the i column of my matrix-- that gives zero, so I'm doing something wrong.
Second I have a Force function that I know is conservative:
F = (yz^2)i + (xz^2 + 2)j + (2xyz -1)k
when I take the partials of the function I get,
Fx = z^2 + 2y
Fy = Z^2 + 2xy
Fz = 2yz + 2xz +2xy
Now, when I place these partials in the top row and place the Function components in the bottom row-- I do not get a zero cross product.
Please tell me what I'm doing wrong.
Thanks
Probably not able to get the partial derivatives of the function right...
Ok, first off, have a Force that is a function of position: F = ax, where a is a constant--I know the solution to the curl is a in the direction of z; not conservative. But, when I set up my cross product matrix I have for the partials in the z and z direction as zero, and the Fy and Fz too. Now this leaves me with only a and ax in the i column of my matrix-- that gives zero, so I'm doing something wrong.
Second I have a Force function that I know is conservative:
F = (yz^2)i + (xz^2 + 2)j + (2xyz -1)k
when I take the partials of the function I get,
Fx = z^2 + 2y
Fy = Z^2 + 2xy
Fz = 2yz + 2xz +2xy
Now, when I place these partials in the top row and place the Function components in the bottom row-- I do not get a zero cross product.
Please tell me what I'm doing wrong.
Thanks