1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Current carrying wire

  1. Nov 6, 2007 #1
    1. The problem statement, all variables and given/known data

    A wire carrying a 27.0A current bends through a right angle. Consider two 2.00mm segments of wire, each 3.00cm from the bend.


    Find the magnitude of the magnetic field these two segments produce at point P, which is midway between them.

    2. Relevant equations

    F = IL x B

    3. The attempt at a solution

    B = F / IL
    = F / 27 x 0.004 m (both 2mm segments combined)

    once again stuck on how to find F, and unsure if i am even using the correct equation. where does the 3cm from the bend bit come into play if at all?
  2. jcsd
  3. Nov 6, 2007 #2


    User Avatar
    Homework Helper

    Relevant equations

    F = IL x B
    It is the force acting on a current carrying conductor in a magnetic field.
    The correct equation is . deltaB = (mu)o/4pi{I*delta L*sin(theta)}/R^2
    where (theta ) is the angle between (delta L) and line joining the point P and mid point of delta L and R is the distance between delta L and P.
    Last edited: Nov 6, 2007
  4. Nov 7, 2007 #3
    ΔB = μo/4π(IΔLsinθ)/R^2

    so I = 27
    θ = 45
    ΔL = 2mm???
    and R can be found using trig.

    so what is μ and o??

    soz just really lost. any help would be great.
  5. Nov 7, 2007 #4


    User Avatar
    Homework Helper

    Field due to two elements =ΔB = 2[μo/4π(IΔLsinθ)/R^2]
    = 2[10^-7*27*2x10^-3*0.707/(1.414*1.5*10^-2)^2]
    = 16.968x10^-6T
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Current carrying wire