Current in a rectangle on a hinge

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Homework Help Overview

The problem involves a rectangular coil of wire carrying a current and positioned in a magnetic field, with the goal of determining the torque acting on the coil about its hinge line. The context is rooted in electromagnetism, specifically the interaction between current-carrying conductors and magnetic fields.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the torque formula and the magnetic moment, with one participant expressing uncertainty about how to begin the calculations. Others provide calculations but question the correctness of the angle used in the torque equation.

Discussion Status

The discussion is ongoing, with participants providing calculations and questioning the assumptions made regarding the angle in the torque formula. There is an indication of productive engagement as participants seek to clarify the reasoning behind the angle used.

Contextual Notes

There is a mention of a specific angle (30°) that may not be appropriate for the calculations, prompting further exploration of the direction of the magnetic moment.

lodovico
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29_46.gif

Homework Statement


Figure 29-36 shows a rectangular, 15-turn coil of wire, 10 cm by 5.0 cm. It carries a current of 0.90 A and is hinged along one long side. It is mounted in the xy plane, at an angle of 30° to the direction of a uniform magnetic field of 0.50 T. Find the magnitude and direction of the torque acting on the coil about the hinge line.

Homework Equations



\tau=μ × B
μ=NiA

The Attempt at a Solution



I don't know how to approach this. I tried to plug in numbers into ^ formula
 
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If you'll show more details of how you tried the calculation, we will be able to see where you're having trouble.
 
τ=μ × B
μ=NiA

τ=NiABsin30
τ=(15)(.9)(.1*.05)(.5)sin30

τ=.16875 Nm
 
lodovico said:
τ=μ × B
μ=NiA

τ=NiABsin30
τ=(15)(.9)(.1*.05)(.5)sin30

τ=.16875 Nm

See if you can figure out why the 30o is not correct here. You'll need to think about the direction of \vec{\mu}
 

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