Current in RLC Series Circuit: Need Help

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The discussion centers on calculating the current in an RLC series circuit with specific component values: a 100-ohm resistor, a 0.01uF capacitor, a 25mH inductor, and a 50V AC voltage source at 1kHz. Participants suggest that the issue may lie in the capacitor's value, as it significantly affects impedance. One contributor confirms that they cannot find any mistakes in the calculations provided. The original poster expresses uncertainty about the capacitor's value and seeks reassurance about their work. Overall, the conversation emphasizes the importance of verifying component specifications in circuit analysis.
IronaSona
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So am trying to find the current in the RLC series circuit ,but i think i have done something wrong ,if anyone could tell me where i went wrong ,it would be great ,thank you

Resistor-100ohms
Capacitor-0.01uF
Inductor-25mH
Voltage Source-50v a.c
1kHz
Capture.PNG
 
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I checked your work and can't spot any mistake. Maybe the mistake is in the given data, are you sure the capacitor value is 0.01uF? Cause that is what makes the impendance big.
 
Delta2 said:
I checked your work and can't spot any mistake. Maybe the mistake is in the given data, are you sure the capacitor value is 0.01uF? Cause that is what makes the impendance big.
o sorry ,i just wasn't 100% sure that it was correct ,just wanted to make sure i have done everything right , thank you
 
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Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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