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Current of Phasor going in CCW direction

  1. Nov 16, 2016 #1
    Hi,

    I feel I have solved this problem correctly (solving for vo(t)), however since the current is going in the ccw direction, would this make the current -5cos(10t - 45) versus 5 cos(10t -45)? This may be a simple question, so I am just making sure. Thanks!
     

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  2. jcsd
  3. Nov 16, 2016 #2

    berkeman

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    Staff: Mentor

    Inverting the amplitude is the same as adding a 180-degree phase shift. To make the rotation direction different, you need a negative sign in a different place...
     
  4. Nov 16, 2016 #3
    I think I understand. A 180 degree phase shift would apply to the -45 degrees. So 5cos(10t + 135)?
     
  5. Nov 16, 2016 #4

    berkeman

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    Staff: Mentor

    Um, no, that's not what I meant.

    Regardless of the problem you posted, if you want the phasor to rotate in the opposite direction, you need to multiply by -1 where in the equation? Think about how each term in the equation affects the function...
     
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