Current of Phasor going in CCW direction

[smstepanic]

Hi,

I feel I have solved this problem correctly (solving for vo(t)), however since the current is going in the ccw direction, would this make the current -5cos(10t - 45) versus 5 cos(10t -45)? This may be a simple question, so I am just making sure. Thanks!

 

[berkeman]

Hi,

I feel I have solved this problem correctly (solving for vo(t)), however since the current is going in the ccw direction, would this make the current -5cos(10t - 45) versus 5 cos(10t -45)? This may be a simple question, so I am just making sure. Thanks!

Inverting the amplitude is the same as adding a 180-degree phase shift. To make the rotation direction different, you need a negative sign in a different place...

 

[smstepanic]

Inverting the amplitude is the same as adding a 180-degree phase shift. To make the rotation direction different, you need a negative sign in a different place...

I think I understand. A 180 degree phase shift would apply to the -45 degrees. So 5cos(10t + 135)?

 

[berkeman]

I think I understand. A 180 degree phase shift would apply to the -45 degrees. So 5cos(10t + 135)?

Um, no, that's not what I meant.

Regardless of the problem you posted, if you want the phasor to rotate in the opposite direction, you need to multiply by -1 where in the equation? Think about how each term in the equation affects the function...