Current value of the scale factor(R₀)?

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The current value of the scale factor (R₀) is not a fixed number, as it can vary based on the cosmological model being used. In cosmology, R(t) represents the scale factor at time t, and at the current epoch, R(t) equals R₀. The relationship a = R(t)/R₀ indicates that R₀ can be normalized to 1 for convenience in calculations. If the universe is not spatially flat, R₀ can be calculated using specific formulas involving parameters like the Hubble constant and density parameters. Ultimately, R₀ is arbitrary in a flat universe and can be adjusted according to the chosen cosmological framework.
EhsanZ
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What is the current value of the scale factor(R₀)?

a= R(t)/R₀

Give me the number.
 
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R0 is the value of R(t) at t=0.
Apart from that, need more information.
 
Since a = R(t)/R0, and we normalise to the current epoch, right now, R(t) = R0
 
<headslap> cosmology forum!
 
Sorry, is that directed at me?
 
No - I don't slap anyone elses head unless there is some sort of contractual obligation.
See post #2 ... mumble mumble I suppose had I shut up people would think I was being clever?
 
e.bar.goum said:
Since a = R(t)/R0, and we normalise to the current epoch, right now, R(t) = R0

Number?
 
It's a scaling factor, there isn't one. Maybe if you be more specific with your problem, we can help you. You can arbitrarily change it depending on your cosmology.
 
If the universe is not (spatially) flat, then

R_0 = \frac{c}{H_0} \sqrt{\frac{k}{\Omega_{m,0} + \Omega_{r,0} + \Omega_{\Lambda,0} - 1}}.
If the universe is (spatially) flat, then R_0 is arbitrary.
 
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