Current & Voltage Relationship in LCR Series Circuit

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In an LCR series circuit, the relationship between current and voltage is determined by the frequency of the applied AC signal relative to the resonance frequency (fr). When the applied frequency (f) is greater than fr, the circuit behaves inductively, causing the current to lag behind the voltage. Conversely, when f is less than fr, the circuit behaves capacitively, resulting in the current leading the voltage. The phase angle can be calculated using the formula tan(φ) = (XL - XC)/R, where XL and XC are the inductive and capacitive reactances, respectively. Understanding these relationships is crucial for analyzing the circuit's behavior at different frequencies.
physicsprasanna
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the question is :
suppose the resonance frequency of the LCR series circuit is fr. Will the current in the circuit lag behind the voltage or lead the voltage in the following cases :
(i) when the applied AC frequency f > fr
(ii) when f < fr

we can say that the current lags behind the voltage when the circuit in inductive. The phase angle can be calculated by \tan\phi=\frac{X_{L}-X_{C}}{R} . But how can we conclude whether XL - XC is postive or not when we are given the applied frequency.

I was able to figure out one thing. When the applied frequency is same as the resonance frequency, XL = XC , which means \tan\phi=0. so the current and voltage are in phase.
 
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physicsprasanna said:
the question is :
suppose the resonance frequency of the LCR series circuit is fr. Will the current in the circuit lag behind the voltage or lead the voltage in the following cases :
(i) when the applied AC frequency f > fr
(ii) when f < fr

we can say that the current lags behind the voltage when the circuit in inductive. The phase angle can be calculated by \tan\phi=\frac{X_{L}-X_{C}}{R} . But how can we conclude whether XL - XC is postive or not when we are given the applied frequency.

I was able to figure out one thing. When the applied frequency is same as the resonance frequency, XL = XC , which means \tan\phi=0. so the current and voltage are in phase.


What you need to do here is sketch a quick phasor diagram of the circuit. The details don't matter, just as long as you have something to work with. Now, both X_C and X_L depend on the frequency of the current in the circuit. So what happens to X_C as we increase the frequency from the resonance frequency? What happens to X_C as we increase the frequency from resonance frequency? What do these changes do to your phasor diagram? From this you can figure out what happens to your phase angle.

-Dan
 
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