Effect of Adding a Third Resistor in Parallel on Series Circuit Current

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When a third resistor R3 is added in parallel to resistor R2, the equivalent resistance (Req) of the parallel combination decreases compared to R2 alone. This reduction in resistance leads to an increase in the total current flowing through R1, as per Ohm's Law (V=I*R). Since the voltage from the emf source remains constant and the overall resistance of the circuit decreases, the current through R1 must increase.
Romperstomper
Resistors R1 and R2 are connected in series to an emf source that has negligible internal resistance. What happens to the current through R1 when a third resistor R3 is added in parallel to R2?

I think it will go up because the Req of R3 and R2 in parallel will be lower than R2. Since V=I*R, if R decreases, then I must increase. Is this true?
 
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Yes, that is true.
 

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