- #1
Miike012
- 1,009
- 0
f= x^2
f' = 2x
f'> 0 in (0, ∞)... f = y increases on this interval
f' < 0 in (-∞,0) f = y decreases on this interval
I don't understand... it is saying that f decrease on (-∞,0) but obviously its not because (∞)^2 = ∞ which is increasing...
Does this mean that the function is decreasing as as x approaches zero from the left?? If it did that would make more sense to me..
f' = 2x
f'> 0 in (0, ∞)... f = y increases on this interval
f' < 0 in (-∞,0) f = y decreases on this interval
I don't understand... it is saying that f decrease on (-∞,0) but obviously its not because (∞)^2 = ∞ which is increasing...
Does this mean that the function is decreasing as as x approaches zero from the left?? If it did that would make more sense to me..