Cuse these difference quotients

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The discussion focuses on evaluating the difference quotient for a given function, specifically f(x) = (x + 7)/(x + 5). Participants emphasize the importance of substituting the function into the difference quotient formula and simplifying it. There is a mention of the relationship between the difference quotient and the slope of the tangent line, highlighting that the limit of the difference quotient as x approaches a is the derivative. One participant expresses confusion about the expected outcome and admits to missing classes, which has affected their understanding. Overall, the conversation centers on clarifying the steps needed to correctly evaluate the difference quotient.
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Cuse these difference quotients!

Homework Statement


http://www.webassign.net/www14/symImages/5/8/30f1e141e81c6a3333af41547f8ff2.gif

Evaluate the difference quotient for the given function

http://www.webassign.net/www14/symImages/4/6/bda668fa415dbf5d0c9c2ba4c031d2.gif

Homework Equations


n/a

The Attempt at a Solution


I seem to have the wrong mindset while doing these.

I got 0.

Actually, I don't really know exactly what I'm even going for here.
 
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It's not zero. It's a function of x. Why don't you show us what you did? Just substitute the given f(x) into the difference quotient.
 


My main thing is that I don't know what the outcome should look like.

It was during the last few weeks of my senior year of high school so I didnt exactly make it to class every day and I missed this stuff. Its coming back to bite me in college now.
 


I told you, just substitute the form for f(x) into the difference quotient and try and do some algebra to simplify it. What is f(5)? This isn't a big conceptual problem.
 


leftyguitarjo said:

Homework Statement


http://www.webassign.net/www14/symImages/5/8/30f1e141e81c6a3333af41547f8ff2.gif

Evaluate the difference quotient for the given function

http://www.webassign.net/www14/symImages/4/6/bda668fa415dbf5d0c9c2ba4c031d2.gif


Homework Equations


n/a


The Attempt at a Solution


I seem to have the wrong mindset while doing these.

I got 0.

Actually, I don't really know exactly what I'm even going for here.

Later on you will see that the slope of the tangent line at a point say P(a,f(a)), is given by:

\lim_{x\rightarrow a}\frac{f(x)-f(a)}{x-a}=f'(a)

And only the quotient \frac{f(x)-f(a)}{x-a} is the slope of secat line.

So, you are given a function f(x) and then asked to find the quotient.

\frac{f(x)-f(5)}{x-5} so what u want to do is replace f(x) with what you are given, in other words, write the function f(x)=... whatever it equals, and then for f(5), you first want to evalulate f(5)=...whatever it equals. You evaluate f(5) by plugging 5 in

f(x)=\frac{x+7}{x+5}
 
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leftyguitarjo said:
My main thing is that I don't know what the outcome should look like.

It was during the last few weeks of my senior year of high school so I didnt exactly make it to class every day and I missed this stuff. Its coming back to bite me in college now.

Dick said "Why don't you show us what you did? " Why will you not do that?
 
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