Cutkosky Cutting Rules: Understanding Rules & Where To Add i

  • Thread starter Thread starter thoughtgaze
  • Start date Start date
  • Tags Tags
    Cutting Rules
thoughtgaze
Messages
74
Reaction score
0
OKay, so whenever I run into explanations on the cutting rules, most of the time I see the statement to replace##\frac{1}{p^2 - m^2 + i\epsilon} \rightarrow -2i\pi \delta(p^2 - m^2)## for each propagator that has been cut

taking note that there is no factor of i in the numerator for ##\frac{1}{p^2 - m^2 + i\epsilon}##

so for example, for ##\phi^3## theory we can have a loop amplitude given by

##iM(p^2) = \frac{(i\lambda)^2}{2} \int \frac{d^4k}{(2\pi)^4}\frac{i}{(k-p)^2 - m^2 + i\epsilon}\frac{i}{k^2 - m^2 + i\epsilon}##

or
##iM(p^2) = -\frac{(i\lambda)^2}{2} \int \frac{d^4k}{(2\pi)^4}\frac{1}{(k-p)^2 - m^2 + i\epsilon}\frac{1}{k^2 - m^2 + i\epsilon}##Making the cut through the diagram, and making the above defined replacement gives

##-\frac{(i\lambda)^2}{2} \int \frac{d^4k}{(2\pi)^4}[-2i\pi \delta((k-p)^2 - m^2)][-2i\pi \delta(k^2 - m^2)]##

upon simplifying we should have...

##-\frac{(\lambda)^2}{2} \int \frac{d^4k}{(2\pi)^2}[\delta((k-p)^2 - m^2)][\delta(k^2 - m^2)]##

which is off, by a minus sign, from the right answer...

I would get the right answer if I made the replacement

##\frac{i}{p^2 - m^2 + i\epsilon} \rightarrow -2i\pi \delta(p^2 - m^2)##
WITH the factor of i in the numerator

instead of ##\frac{1}{p^2 - m^2 + i\epsilon} \rightarrow -2i\pi \delta(p^2 - m^2)##
WITHOUT the factor of i in the numerator

What am I doing wrong?
 
Physics news on Phys.org
The main thing I see you're doing wrong is evaluating Feynman diagrams.
 
  • Like
Likes Frico
Oh? Well how so?
 
@thoughtgaze
I have been using Cutkosky's cutting rules extensively in my summer project but I still regard myself as an amateur in QFT so please take everything I am saying with a pinch of salt as they say :) The replacement of the off shell propagator terms with delta functions when we take a 'cut' is given by, as far as I am aware, ##(k^2-m^2+i\epsilon)^{-1} \rightarrow 2 \pi \delta(k^2-m^2)##.

The factors of ##i## come into play depending on whether we are using the normal or complex conjugated version of the Feynman rules. Given a cut diagram, there is a convention that we label the vertices of the diagram black or white, black vertices follow standard Feynman rules and are accompanied by a factor of ##i## and white ones the complex conjugated version so come with a ##-i##. In this set up, there is usually a corresponding theta function in the replacement above of the propagator terms so that energy flow from black to white vertices is counted positively but I am not sure if you are perhaps using another convention.
 
Interesting, I have not heard of this convention to treat the vertices differently by complex conjugation. Do you have any references for this particular notion?

Also, I have not seen ##(k^2-m^2+i\epsilon)^{-1} \rightarrow 2 \pi \delta(k^2-m^2)## in any reference I have, for example, peskin&schroeder eq. 7.56
 
Apologies for delay in replying,
thoughtgaze said:
Interesting, I have not heard of this convention to treat the vertices differently by complex conjugation. Do you have any references for this particular notion?
See for example pages 9-10 of this paper http://arxiv.org/pdf/1401.3546v2.pdf.
 
Back
Top