Cuttoff frequwncy for an x-ray tube

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SUMMARY

The cutoff frequency for an x-ray tube operating at 44kV can be calculated using the formula frequency = work function/h. The correct conversion from kilovolts to electronvolts is essential, where 44kV equals 44000eV. The accurate value for Planck's constant is 6.626E-34 J·s, not 1.626E-34 J·s. Correcting this value resolves the calculation error.

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  • Understanding of x-ray tube operation and physics
  • Familiarity with the concept of electronvolts (eV)
  • Knowledge of Planck's constant and its significance in quantum mechanics
  • Basic skills in unit conversion between kilovolts and electronvolts
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How would you calculate the cutoff frequency of an x-ray tube operating at 44kV? I am using frequency = work function/h. I have (44000eV x 1.602E-19J)/1.626E-34 but my answer is wrong. I'm thinking that I converted kV to eV incorrectly, but I'm not sure.
Thanks.
 
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ladiebug511 said:
How would you calculate the cutoff frequency of an x-ray tube operating at 44kV? I am using frequency = work function/h. I have (44000eV x 1.602E-19J)/1.626E-34 but my answer is wrong. I'm thinking that I converted kV to eV incorrectly, but I'm not sure.
Thanks.

Your value for Planck's constant is wrong (that 1 should be a 6). Does that fix it?
 
hage567 said:
Your value for Planck's constant is wrong (that 1 should be a 6). Does that fix it?

Yes. Thanks for pointing out my stupid mistake :) Sometimes it just takes a fresh set of eyes.
 

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