Cyclic Subgroup H=<9> of Z30: List and Find Elements

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1. (a) List all elements in H=<9>, viewed as a cyclic subgroup of Z30
(b) Find all z in H such that H=<z>





I'm thinking that H=<9> = {1,7,9} (viewed as a cyclic subgroup of Z30) is this correct?
And could someone explain what (b) is asking in other terms?
 
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tasha10 said:
I'm thinking that H=<9> = {1,7,9} (viewed as a cyclic subgroup of Z30) is this correct?
And could someone explain what (b) is asking in other terms?

No that is not correct. Z30 is an additive group so H=<9> contains 9, 9+9, 9+9+9 etc.

Part (b) asks which elements of H could produce H by just adding it to itself repeatedly
 
so {9,18,27}?
 
No, quite a few more. What do you get if you add 9 to 27 in Z30?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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