Cylinderical reigon and potential difference

AI Thread Summary
The discussion focuses on calculating the potential difference between two points, A and B, in a cylindrical region with a uniform charge density of 3.0 μC/m. The potential difference is determined using the equation ΔV = -∫E·dr, where E is the electric field derived from the charge density. The electric field is calculated using E = λ/(ε₀ * 2πr), leading to an integral that evaluates the potential difference between the two specified distances from the symmetry axis. The correct answer for the potential difference VA – VB is +20 mV. The solution highlights the importance of recognizing the position of point A within the charged region.
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Homework Statement


The charge of density 3.0 μC/m fills a long cylindrical region having a 2.0-cm radius. If point A is 1.0 cm from the symmetry-axis and point B is 2.0 cm from the symmetry-axis, what is the potential difference VA – VB?
a . –25 mV

b. +42 mV

c. –42 mV

d. +25 mV

e. +20 mV <- answer

Homework Equations


- integral( E . dr) = delta V

The Attempt at a Solution


EA = Q/eo
E(2*pi*r*h) = lambda * h / eo
E = (lambda) /( eo * 2 * pi * r)
-integral(lambda/eo* 2 * r * pi) dr from 0.01 ro 0.02 <--- gives me the wrong answer
 
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yes. did you notice A is 'inside' the charge ?
 
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