- #1
gracy
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In the link given below
http://science.uvu.edu/ochem/index.php/alphabetical/g-h/haworth-formula/
In step 3 last line it is written that 1 and 2 both represent D glucose,but how?As penultimate carbon no 5 has H on right side rather than OH,so it should be L glucose.
http://science.uvu.edu/ochem/index.php/alphabetical/g-h/haworth-formula/
In step 3 last line it is written that 1 and 2 both represent D glucose,but how?As penultimate carbon no 5 has H on right side rather than OH,so it should be L glucose.