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Blues_MTA
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According to http://www.aveox.com/DC.aspx" The way to calculate the output of a DC motor in kRPMs is the formula
RPM of motor: kRPM = (V - RmI) / Kb
V= Voltage
Rm = Terminal Resistance
I = Current
Kb = Voltage Constant (V/kRPMs)
This insinuates that an increase in amperage leads to a decrease in RPMs? How is that Possible?
I know that Current:Torque and Voltage:Speed, but isn't Voltage = I*R, so an increase in current should consequently lead to an incresed voltage?
RPM of motor: kRPM = (V - RmI) / Kb
V= Voltage
Rm = Terminal Resistance
I = Current
Kb = Voltage Constant (V/kRPMs)
This insinuates that an increase in amperage leads to a decrease in RPMs? How is that Possible?
I know that Current:Torque and Voltage:Speed, but isn't Voltage = I*R, so an increase in current should consequently lead to an incresed voltage?
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