DC Network theorems Norton’s and Thevenin’s theorem

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SUMMARY

The discussion focuses on applying Norton’s and Thevenin’s theorems to calculate power dissipation in a 4Ω resistor within a circuit powered by a 60V supply. The circuit includes resistors of 10Ω, 20Ω, 5Ω, 2Ω, 1.5Ω, and 1Ω. The user calculated the current through the 4Ω resistor as 1.02A, resulting in a power dissipation of 4.426W. Additionally, the user attempted to find the load value for maximum power transfer, yielding a current of 1.10A and a power transfer of 65.945W.

PREREQUISITES
  • Norton’s Theorem
  • Thevenin’s Theorem
  • Basic circuit analysis techniques
  • Power calculation formulas (P = I^2R)
NEXT STEPS
  • Study the application of Norton’s Theorem in complex circuits
  • Explore Thevenin’s Theorem for load analysis
  • Learn about maximum power transfer theorem
  • Practice circuit analysis with various resistor configurations
USEFUL FOR

Electrical engineering students, circuit designers, and anyone looking to deepen their understanding of circuit analysis using Norton’s and Thevenin’s theorems.

steven1988
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hi,
thanks for taking time to try and help me out, i have hit a brick wall with these questions, i have made an attempt and don't no where to go from there, and feed back would be great thanks a lot...

The problem
Using both Norton’s and Thevenin’s theorem determine the power dissipated in the 4Ω resistance.

If the 4Ω resistance was removed calculate the value of load that will result in maximum power being transferred

Calculate the value of power transferred

the circuit has a:-
60 V supply
10Ω
10Ω
20Ω




1.5Ω


Homework Equations


I = V
Z
P= I^2R

The Attempt at a Solution


I = V
Z
= 60
58.5
= 1.02
P= I^2R
= 1.02^2 * 4
= 4.426 W
I = V
Z
= 60
54.5
1.10
P= I^2R
= 1.10^2 * 54.5
= 65.945 w
 
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