I DDWFTTW: Looking for the least confusing explanation

Click For Summary
A cart can travel downwind faster than the wind due to the interaction between its wheels and a propeller, which generates thrust by exploiting the apparent headwind created by its own motion. This phenomenon relies on the principles of forces and momentum rather than work done, as the frame of reference significantly affects the interpretation of energy transfer. The cart's wheels drive the propeller, allowing it to extract energy from the wind while the ground provides a stable reference point. The discussion emphasizes the importance of clearly defining frames of reference when analyzing the mechanics involved in this scenario. Ultimately, understanding the forces at play is crucial for grasping why a DDWFTTW vehicle can achieve speeds exceeding that of the wind.
  • #61
jbriggs444 said:
In a downwind configuration, the relative headwind is passing slowly and the ground is passing rapidly. You win by using a propeller to gain high thrust from the wind with a low power requirement while the wheels provide high power from the ground at an expense of low drag.
Well, the physics professors think it cannot possibly be that simple:

 
Physics news on Phys.org
  • #62
I just watched a new Veritasium video where he announces the winning of the bet and does a very good job of describing the situation.
 
  • Like
Likes A.T., hutchphd, anorlunda and 1 other person
  • #63
I think it is beneficial to everyone to debate things like that in public. I'll disagree with Veritasium on the last thing he said in the video. "Let's hope that this video puts the issue to rest, once and for all." In fact, I'll wager that more words, both for an against, will continue in this thread.
 
  • #64
anorlunda said:
I think it is beneficial to everyone to debate things like that in public. I'll disagree with Veritasium on the last thing he said in the video. "Let's hope that this video puts the issue to rest, once and for all." In fact, I'll wager that more words, both for an against, will continue in this thread.
Hope springs eternal, but that proposed wager looks pretty darned safe for you.
 
  • #65
A.T. said:
Well, the physics professors think it cannot possibly be that simple:


He may think that, but he's wrong. From the frame of the cart, the prop is acting exclusively as a prop. I suppose you could make an argument that it's acting as a "turbine" in the frame of the ground because the wind in its wake is traveling slower than the surrounding air, but that argument would also make the propeller of every powerboat traveling downriver also a "turbine" by the same logic (and every airplane with a tailwind).
 
  • #66
cjl said:
He may think that, but he's wrong. From the frame of the cart, the prop is acting exclusively as a prop. I suppose you could make an argument that it's acting as a "turbine" in the frame of the ground because the wind in its wake is traveling slower than the surrounding air, but that argument would also make the propeller of every powerboat traveling downriver also a "turbine" by the same logic (and every airplane with a tailwind).
The argument was more nuanced than that. The [mistaken] claim was that due to wind gusts, the propeller was intermittently acting as a turbine, harvesting energy and then as a prop, generating thrust. Together with an argument about measurement error (wind gradient with height and selective reporting), the claim was that it was all effectively smoke and mirrors.
 
  • #67
Ah. Well, that's also incorrect (as has been explained here many times by many others).
 
  • Like
Likes A.T. and jbriggs444
  • #68
cjl said:
He may think that, but he's wrong. From the frame of the cart, the prop is acting exclusively as a prop. I suppose you could make an argument that it's acting as a "turbine" in the frame of the ground because the wind in its wake is traveling slower than the surrounding air, but that argument would also make the propeller of every powerboat traveling downriver also a "turbine" by the same logic (and every airplane with a tailwind).
Kusenko is not using an energy based definition of "turbine" (which would be frame dependent as you note). He is explicitly saying that the aerodynamic torque on the rotor has the same direction as the torque on the rotor transferred from the wheels and the rotation direction of the rotor:

https://docs.google.com/presentatio...KDkhEfN898K4/edit#slide=id.gb6e540a45a_618_51

Alexander Kusenko said:
When the car is moving faster than the wind, the passing air pushes the propeller in the same direction as the wheels push it. This has been a subject of discussion, and Blackbird has a ratchet to prevent the propeller from actively spinning the wheels, but the ratchet does not keep the propeller’s wind power from spinning the propeller itself, adding the torque in the same direction as the wheels.

I show why this is impossible here:
https://www.physicsforums.com/threa...ast-confusing-explanation.896869/post-6507170
 
Last edited:
  • #69
jbriggs444 said:
The argument was more nuanced than that. The [mistaken] claim was that due to wind gusts, the propeller was intermittently acting as a turbine, harvesting energy and then as a prop, generating thrust. Together with an argument about measurement error (wind gradient with height and selective reporting), the claim was that it was all effectively smoke and mirrors.
That's his initial arguments before the bet. But after conceding the wager he developed this prop & turbine at the same time (not intermittently) theory. See slide 6 here:
https://docs.google.com/presentatio...KDkhEfN898K4/edit#slide=id.gb6e540a45a_618_51

Kusenko still claims that the pure propeller explanation is wrong. and that he merely lost the bet on a technicality:
Kusenko said:
Technically, my wager with Derek Muller stated as part of the claim that “the propeller works like a fan rather than a wind turbine”, which is incorrect. The propeller acts as both a fan and a turbine, and the power is contributed by both moving media in a somewhat symmetrical manner.
 
Last edited:
  • #70
Trying to wrap my head around it with the propeller proved confusing, so I thought up an alternative...

and somebody beat me to it.
 
Last edited:
  • #71
Derek has posted the entire discussion with Kusenko that preceded the wager. I'm linking to the timepoint, where Derek asks him about connecting two boats with downwind velocity component > windspeed (which Kusenko accepts as achievable by a boat), and thus creating a craft that goes DDWFTTW. Kusenko just waves his hands, and claims this has no relation to the propeller vehicle, because there is no wheel in the sailboat analogy.



Here is an animation that explains how the coupling to the wheels forces each section of the propeller blade to move across the wind:



Just like the keel forces the sail to move across the wind when downwind velocity component > windspeed:



I posted the vectors for both situations here:
https://www.physicsforums.com/threa...ast-confusing-explanation.896869/post-6499006
 
Last edited:
  • #72
I've been searching in vane for the parts list people were using to build the treadmill models. Was it included in one of the treadmill test videos, or was it included here?
 
  • #73
rcgldr said:
I've been searching in vane for the parts list people were using to build the treadmill models. Was it included in one of the treadmill test videos, or was it included here?

There is a part list in the video description here:

 
Last edited:
  • #74
rcgldr said:
I've been searching in vane
:DD Freudian slip?
 
  • Like
  • Haha
Likes russ_watters, collinsmark and DaveC426913
  • #75
A.T. said:
There is a part list in the video description here.

I meant the old ones from 10 years ago. No 3d printing required, and they were lighter. Several of these were made by different people here at Physics Forums, and a parts list posted somewhere.



"searching in vane" - this pun was caught a bit sooner that I thought it would be.
 
Last edited:
  • Like
Likes collinsmark and pbuk
  • #76
rcgldr said:
I meant the old ones from 10 years ago. No 3d printing required, and they were lighter.
Here
 
  • #77
I just read those threads from 2008. Wow! There were a lot of posts back then. Most of the posts in this thread repeat points made 2 or 3 times before.
 
  • Like
Likes russ_watters
  • #78
A.T. said:
Thanks.
 
  • #79
jbriggs444 said:
No, I think we're all good and in agreement. Device works, Propeller explanation is good.
Well, I'm not in agreement.
The device does not work.
Even Kusenko said so.
 
  • #80
All we have is definitive theoretical and experimental evidence. Seems pretty weak to me.
 
  • Haha
  • Like
Likes A.T., pbuk, DaveC426913 and 2 others
  • #81
[Moderator Note -- sub-thread merged into this main thread]

Having seen some discussion of FTTWDDW in the past on PF, I thought people might be interested in Veritasium's latest videos:
Original (land car) experiment
Enhanced "proof" to settle a $10k bet with physics prof
No doubt it's a bit light for PF, but the second one certainly convinced me he could be right.

Edit: Apologies for this post. I did search for this thread, but did not find it, perhaps because I used the wrong acronym. But now that I've looked at recent posts, I can see you've already discussed it and some of my searches should have found those posts?

Thanks to Mods for moving it, but they are welcome to delete it since it adds nothing to what's gone before.
 
Last edited:
  • #82
You could use this to power an airplane - until it left the ground.
 
Last edited:
  • #83
Plus this one: How to build your own.
 
  • #84
It seems to me that the reason the math blows up in the solutions discussed in the Veritasium videos as well as the physics papers referenced is that everyone ignores the increased velocity of the air due to the fan. They use the speed of the air through the fan as V-W and therefore the fan power as F(V-W), where V is the speed of the car relative to the ground and W is the speed of the wind relative to the ground. But they ignore the delta V induced by the fan motion. It should be V + delta V - W. Add this and you no longer have the divide by zero problem without any need for complex fan efficiency equations. And you have the correct power when the wind speed matches the vehicle speed.

The increased velocity of the air molecules then manifests as increased pressure behind the fan.

Right?
 
Last edited:
  • Like
Likes electrodacus and ridgerunner
  • #85
Ivan Seeking said:
It seems to me that the reason the math blows up in the solutions discussed in the Veritasium videos
Have you read this entire thread? Have you watched this video?

 
  • #86
anorlunda said:
Have you read this entire thread? Have you watched this video?


Yes I was quoting their equation that fails.

Derek justifies it by referencing a more complex equation needed for the prop efficiency but that doesn't seem to be necessary to make sense of things. It seems to me that they have missed a key term - the energy added to the air by the fan.
 
Last edited:
  • #87
Ivan Seeking said:
Yes I was quoting their equation that fails.

Derek justifies it by referencing a more complex equation needed for the prop efficiency but that doesn't seem to be necessary to make sense of things. It seems to me that they have missed a key term - the energy added to the air by the fan.
If one hypothesizes (as the simplistic equation requires) an arbitrarily large propeller rotating at an arbitrarily small rotation rate with an arbitrarily large torque from a transmission with an arbitrarily high gear ratio then an arbitrarily large thrust can be obtained, even without 100% efficiency.

The larger you make the prop, the larger the deflected air mass becomes, the lower the imparted delta V needs to be and the problem with energy loss due to induced drag can be made as small as one pleases.

[Obviously, there are practical limitations with material rigidity and the finite depth of the atmosphere]

For any fixed finite propeller size, infinite torque means zero rotation rate and you get zero propulsion from an infinite gear ratio.
 
Last edited:
  • Like
Likes Ivan Seeking, A.T. and cjl
  • #88
Ivan Seeking said:
It should be V + delta V - W. Add this and you no longer have the divide by zero problem without any need for complex fan efficiency equations.
That just shifts the divide by zero problem to some speed slightly less than wind speed, where V + delta V - W = 0.
 
  • Like
Likes Ivan Seeking
  • #89
Ivan Seeking said:
It seems to me that the reason the math blows up in the solutions discussed in the Veritasium videos as well as the physics papers referenced is that everyone ignores the increased velocity of the air due to the fan. They use the speed of the air through the fan as V-W and therefore the fan power as F(V-W), where V is the speed of the car relative to the ground and W is the speed of the wind relative to the ground. But they ignore the delta V induced by the fan motion. It should be V + delta V - W. Add this and you no longer have the divide by zero problem without any need for complex fan efficiency equations.
As @rcgldr notes, it doesn't help at all, because you just have another point where the airspeed you use is zero. And additionally you now need to know delta V. The math doesn't blow up at this point, when you include the propeller efficiency, which also goes to zero, when the airspeed does.

But all this is not needed to show that steady state above wind-speed is possible, regardless how it got there. For this the simple idealized formula that the video shows is enough, since it shows excess thrust, which can account for the loses.

The static thrust estimation is only needed to predict the acceleration phase. But if you want to do that, then you also have to consider the propeller working in reversed flow below wind speed, basically with negative efficiency.
 
Last edited:
  • Like
Likes Ivan Seeking
  • #90
A.T. said:
But all this is not needed to show that steady state above wind-speed is possible, regardless how it got there. For this the simple idealized formula that the video shows is enough, since it shows excess thrust, which can account for the loses.

The static thrust estimation is only needed to predict the acceleration phase. But if you want to do that, then you also have to consider the propeller working in reversed flow below wind speed, basically with negative efficiency.
But the equation is wrong. Where does it show the energy added to the air moving through the prop area?
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 77 ·
3
Replies
77
Views
5K
Replies
15
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
6
Views
2K
  • · Replies 40 ·
2
Replies
40
Views
7K
  • · Replies 86 ·
3
Replies
86
Views
8K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 87 ·
3
Replies
87
Views
5K
  • · Replies 48 ·
2
Replies
48
Views
5K