Two automobiles of 540 and 1400 kg collide head-on while moving at 80km/h in opposite directions. After the collision the automobiles remain locked together. The front end of each automobile crumples by 0.60 m during the collision. Find the acceleration (relative to the ground) of the passenger compartment of each automobile; make the assumption that these accelerations are constant during the collision.
displacement =.6 m
velocity after collision=9.9 m/s
The Attempt at a Solution
I know the momentum is constant--(68800 kg*m/s) and the kinetic energy before and after the collision is--(4.8*10^5 J, 9.4*10^4 J). I think that m1*a1=m2*a2, not too sure about that. After that I am not sure how to calculate the de-acceleration without knowing the impact time.