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## Homework Statement

Two automobiles of 540 and 1400 kg collide head-on while moving at 80km/h in opposite directions. After the collision the automobiles remain locked together. The front end of each automobile crumples by 0.60 m during the collision. Find the acceleration (relative to the ground) of the passenger compartment of each automobile; make the assumption that these accelerations are constant during the collision.

v=80 km/h

m1= 540

m2= 1400

displacement =.6 m

a1= ?

a2= ?

velocity after collision=9.9 m/s

## Homework Equations

P=mv

KE=(1/2)mv^2

F=ma

## The Attempt at a Solution

I know the momentum is constant--(68800 kg*m/s) and the kinetic energy before and after the collision is--(4.8*10^5 J, 9.4*10^4 J). I think that m1*a1=m2*a2, not too sure about that. After that I am not sure how to calculate the de-acceleration without knowing the impact time.

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