DE Derivative Using Euler's Method

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SUMMARY

The discussion centers on using Euler's method to solve the differential equation modeling the velocity of a skydiver, represented as m*dv/dt = mg - k*v^2. For a skydiver with a mass of 54 kg and a drag coefficient of 0.18 kg/m, the calculated terminal velocity is 54.2218 m/s. The diver reaches 95% of this terminal velocity at approximately 51.5107 seconds after jumping from the plane. The approach and calculations presented are confirmed as correct by other participants in the discussion.

PREREQUISITES
  • Understanding of differential equations and their applications
  • Familiarity with Euler's method for numerical solutions
  • Knowledge of physics concepts such as terminal velocity and drag coefficients
  • Basic proficiency in mathematical modeling and numerical analysis
NEXT STEPS
  • Study the derivation and application of Euler's method in greater detail
  • Explore advanced numerical methods for solving differential equations, such as Runge-Kutta methods
  • Investigate the effects of varying drag coefficients on terminal velocity
  • Learn about the physical principles governing free fall and air resistance
USEFUL FOR

This discussion is beneficial for physics students, mathematicians, and engineers interested in numerical methods for solving differential equations, particularly in the context of motion and forces acting on objects in free fall.

MechE2015
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Homework Statement



The velocity v of a skydiver is well modeled by a differential equation:

m*dv/dt = mg - k*v^2

Where m is the mass of the skydiver, g = 9.8 m/s^2 is the gravitational constant, a k is the drag coefficient determined by the position of the diver during the dive. Consider a diver of mass m = 54 kg with a drag coefficient of 0.18 kg/m. Use Euler's method to determine how long it will take the diver to reach 95% of her terminal velocity after she jumps from the plane.

Homework Equations



Euler's method:
y[k+1] = y[k] + f(t[k],y[k])*DeltaT

The Attempt at a Solution



I placed the constants into the equation to get:
dv/dt = (529.2 - 0.18*v^2) / 54

Then, using Euler's method with a very small delta T, I find terminal velocity to be 54.2218. This would mean that the diver reaches 95% of terminal velocity at approximately 51.5107.

1) Is this the correct way of approaching the problem? Is my terminal velocity correct?
2) From here I suppose I would just find the point where y[n] = 51.5107?

If anyone can help me I would greatly appreciate it!
 
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MechE2015 said:

Homework Statement



The velocity v of a skydiver is well modeled by a differential equation:

m*dv/dt = mg - k*v^2

Where m is the mass of the skydiver, g = 9.8 m/s^2 is the gravitational constant, a k is the drag coefficient determined by the position of the diver during the dive. Consider a diver of mass m = 54 kg with a drag coefficient of 0.18 kg/m. Use Euler's method to determine how long it will take the diver to reach 95% of her terminal velocity after she jumps from the plane.

Homework Equations



Euler's method:
y[k+1] = y[k] + f(t[k],y[k])*DeltaT

The Attempt at a Solution



I placed the constants into the equation to get:
dv/dt = (529.2 - 0.18*v^2) / 54

Then, using Euler's method with a very small delta T, I find terminal velocity to be 54.2218. This would mean that the diver reaches 95% of terminal velocity at approximately 51.5107.

1) Is this the correct way of approaching the problem? Is my terminal velocity correct?
2) From here I suppose I would just find the point where y[n] = 51.5107?

If anyone can help me I would greatly appreciate it!

Sure, terminal velocity is where dv/dt=0. You don't even need the numerical solution to find the terminal velocity. So that part looks ok, and yes, find where y[n] = 51.51.
 
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