Dealing with Input Offset Voltages in Op-Amp Circuits

AI Thread Summary
The discussion focuses on addressing input offset voltages in op-amp circuits, particularly in the context of designing a sound level meter. The user successfully simulated a circuit using Mentor Graphics but struggles with manual calculations for achieving a specific output voltage of -10mV. Key calculations involve using a potential divider approach with dual power supplies and equivalent resistances. Participants emphasize the variability of input offset voltages due to temperature and component differences, suggesting the need for a reliable op-amp choice. The user expresses satisfaction with the circuit's overall performance, achieving a 60dB dynamic range.
jeuhyis
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Hi first time poster. I'm a little stuck, through trial and error on Mentor graphics I was able to create the attached circuit. Using +&- 9V supply rails I managed to output -10mV, which I required. Now I have come round to try and work it out by hand I'm struggling to remember how! I know that the first part is basically a potential divider but how does this work with a positive and negative voltage?

Any help greatly appreciated
 

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Treat it as a divider between 18V and 0V and then subtract 9V from the output voltage.
 
The two supplies on the left and the two resistors can be replaced with an equivalent single supply and single resistor.

R = 10*8.87/(10+8.87) KOhms

V = (9+9)8.87/(10+8.87) - 9 Volts
 
Phrak said:
The two supplies on the left and the two resistors can be replaced with an equivalent single supply and single resistor.

R = 10*8.87/(10+8.87) KOhms

V = (9+9)8.87/(10+8.87) - 9 Volts

So therefore using this
R = 10*8.87/(10+8.87) KOhms = 4.7KOhms

V = (9+9)8.87/(10+8.87) - 9 Volts = -0.53895V

So then is there some calculation required using the 500K and 1K utilising the -0.53895V to reach the 10mV?

Thanks for your help so far
 
That's an odd combination of components. What's it for?

Vout = -0.539[10/(500 + 4.7 + 10)]

not 10mV, but -10mV
 
Its for an input offset voltage on the non-inverting input of an op-amp to give a zero voltage output. I spent ages designing an RMS circuit for a sound level meter and then I hit this problem. Managed to figure out what offset was required simulated that circuit but then I could remember how to hand calculate!
 
jeuhyis said:
Its for an input offset voltage on the non-inverting input of an op-amp to give a zero voltage output. I spent ages designing an RMS circuit for a sound level meter and then I hit this problem. Managed to figure out what offset was required simulated that circuit but then I could remember how to hand calculate!

Input offset voltages vary with temperature, and from part-to-part. What opamp are you using? There may be a more reliable way to deal with the input offset voltage. Can you post your schematic?
 
berkeman said:
Input offset voltages vary with temperature, and from part-to-part. What opamp are you using? There may be a more reliable way to deal with the input offset voltage. Can you post your schematic?

Here's a screen shot of what I've been designing. I am happy with the overall performance of the circuit, its being used within a group to create a sound level meter, and i have this working as a Type 0 with a 60dB dynamic range.
 

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