Decimal Expansion Homework: Terminating & Non-Terminating 9's

cragar
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Homework Statement


How many decimal expansions terminate in an infinite string of 9's?
How many dont?

The Attempt at a Solution


If we have a number terminate with an infinite amount of 9's then it will be a rational number.
So there would be countably many of these.

And since irrational numbers do not end with all 9's then their would be
uncountably many of them that do not.
 
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cragar said:

Homework Statement


How many decimal expansions terminate in an infinite string of 9's?
How many dont?

The Attempt at a Solution


If we have a number terminate with an infinite amount of 9's then it will be a rational number.
So there would be countably many of these.

And since irrational numbers do not end with all 9's then their would be
uncountably many of them that do not.

That's the right idea.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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