Decrease of Solar radius per year using Virial Theorem

AI Thread Summary
The discussion centers on calculating the decrease in the Sun's radius per year using the Virial Theorem, assuming energy production is due to slow compression rather than fusion. Participants clarify that \(L_G\) represents the rate of energy loss due to gravitational potential energy and rotational kinetic energy as the Sun contracts, which should equal the Sun's luminosity. The luminosity of the Sun is given as approximately \(3.839 \times 10^{26}\) watts, which is essential for solving for the change in radius over time. The conversation emphasizes the importance of understanding the relationship between gravitational energy loss and the Sun's radiated energy. Overall, the thread provides insights into astrophysical calculations related to stellar dynamics.
CharlesDamle
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Homework Statement
Calculate the decrease in Solar radius per year using the Virial Theorem
Relevant Equations
L_G = -(1/2) * (GM^2/R^2) * (dR/dt)
Hello, I am trying to solve this question:

Assume that the Sun's energy production doesn't happen by fusion processes, but is caused by a slow compression and that the radiated energy can be described by the Virial Theorem: $$L_G = - \frac{1}{2} \frac{GM^2}{R^2} \frac{dR}{dt} $$
How much must the Sun's radius decrease per year in order to uphold its energy production?


I'm not quite sure what LG is, but I've tried inserting the gravitational term of the Virial Theorem, but that gives a decrease in solar radius of the entire Sun's radius per second... A hint would be amazing, if anyone knows what LG represents.

Cheers
 
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If you replace each variable on the right with the units of the variable then reduce the result, the remaining units should give you a big clue as to what ##L_G## might be.
 
I know it's energy, if that's what you're hinting :D
 
CharlesDamle said:
I know it's energy, if that's what you're hinting :D
##L_G## is not energy. But, it's closely related to energy. What did you get for the overall units of the right-hand side of the expression for ##L_G##?
 
Ahh it is J / s right?
 
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CharlesDamle said:
Ahh it is J / s right?
Yes :oldsmile:
 
Right, so I want to solve for (dR/dt) to get the change over time, so I can't multiply by dt on both sides to get energy on the left hand side. Not quite sure what to do with LG
 
Do you know what ##L_G## stands for? The value of ##L_G## is easy to find with a web search. Or, maybe the value of ##L_G## was given in your course or textbook.
 
No, I have no idea. I looking for it in the Virial Theorem section, but without any luck. It hasn't been mentioned in the chapter we've been reading this week.
 
  • #10
##L_G## is the rate at which rotational kinetic energy plus gravitational PE is lost as the radius of the sun contracts. You are considering a hypothetical model where this loss of energy is converted into the energy radiated by the sun. So, you want ##L_G## to match the rate at which energy is radiated by the sun. The rate at which the sun radiates energy is called the sun's luminosity. So you will need to look up the luminosity of the sun.
 
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Ahh, okay we always write it with other symbols. I have no idea why they changed it, but naturally I know what luminosity is.. :woot: Alright, so I set it equal LG = 3.839 * 1026 W and solve for(dR/dt)?
Thank you so much for explaining this!
 
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  • #12
CharlesDamle said:
Ahh, okay we always write it with other symbols. I have no idea why they changed it, but naturally I know what luminosity is.. :woot: Alright, so I set it equal LG = 3.839 * 1026 W and solve for(dR/dt)?
Thank you so much for explaining this!
Good. This is an interesting calculation.
 
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