I Defining Del in Index Notation: Which Approach is Appropriate?

member 428835
Hi PF!

Which way is appropriate for defining del in index notation: ##\nabla \equiv \partial_i()\vec{e_i}## or ##\nabla \equiv \vec{e_i}\partial_i()##. The two cannot be generally equivalent. Quick example.

Let ##\vec{v}## and ##\vec{w}## be vectors. Then $$\nabla \vec{v} \cdot \vec{w} = \partial_i(v_j \vec{e_j})\vec{e_i} \cdot u_k \vec{e_k}\\ = \partial_i(v_j \vec{e_j}) u_i$$ yet using the other definition for del implies $$\nabla \vec{v} \cdot \vec{w} = \vec{e_i} \partial_i(v_j \vec{e_j}) \cdot u_k \vec{e_k}\\=\vec{e_i} v_ju_k (\partial_i(\vec{e_j}) \cdot \vec{e_k}) + \vec{e_i} u_j \partial_i(v_j)$$
 
Physics news on Phys.org
joshmccraney said:
Hi PF!

Which way is appropriate for defining del in index notation: ##\nabla \equiv \partial_i()\vec{e_i}## or ##\nabla \equiv \vec{e_i}\partial_i()##.

The second. In orthogonal coordinates \nabla = \sum_i \mathbf{e}_i h_i \partial _i and in non-cartesian coordinates h_i is generally a non-constant function of position.
 
pasmith said:
The second. In orthogonal coordinates \nabla = \sum_i \mathbf{e}_i h_i \partial _i and in non-cartesian coordinates h_i is generally a non-constant function of position.
So is ##h_i = |\partial_i \vec{r}|## where ##\vec{r}## is the position vector, expressed in cartesian coordinates as ##\vec{r} = x \hat{i} + y \hat{j} +z \hat{k}##?
 

Similar threads

Replies
4
Views
7K
Replies
2
Views
2K
Replies
2
Views
4K
Replies
4
Views
2K
Replies
3
Views
2K
Replies
6
Views
3K
Replies
9
Views
3K
Back
Top