Definition of a unique function

jonsploder
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Hi all, I'm wondering whether an expression which is used to describe a function in a certain domain is a different function for the same expression with a differing domain.

For example: expression; x^2.
f(x) = x^2 for domain {1 < x < 10}
f(x) = x^2 for domain {10 < x < 11}

Are these two f(x)'s the same function, or different functions, by definition. I couldn't be sure by Wikipedia, and it's a difficult question to type into a search engine.
 
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hi jonsploder! welcome to pf! :smile:
jonsploder said:
… Are these two f(x)'s the same function, or different functions …

they're different

they're both restrictions of the same function defined on the whole of R :wink:
 
Thanks for the welcome, and the reply.
I know that they are different, however I was wondering, by the most formal definition of a function, whether they are different functions, or if indeed the domain of a function constitutes its identity as a function.
 
jonsploder said:
I know that they are different, however I was wondering, by the most formal definition of a function, whether they are different functions, or if indeed the domain of a function constitutes its identity as a function.

they're functions, and they're different

so they're different functions

the definition of a function includes its range and domain: different range and/or domain, different functions
 
jonsploder said:
Thanks for the welcome, and the reply.
I know that they are different, however I was wondering, by the most formal definition of a function, whether they are different functions, or if indeed the domain of a function constitutes its identity as a function.

The domain and codomain are part of the definition of a function.

Two functions f : A \to B and g : C \to D are equal if and only if A = C and B = D and for all a \in A, f(a) = g(a).
 
pasmith said:
Two functions f : A \to B and g : C \to D are equal if and only if A = C and B = D and for all a \in A, f(a) = g(a).
This definition is exactly correct. That should be your definition.

...

It's worth noting, however, that sometimes people get lazy about codomains and say f : A \to B and g : C \to D are equal when A = C and for all a \in A, f(a) = g(a) \in B\cap D.
 
economicsnerd said:
It's worth noting, however, that sometimes people get lazy about codomains and say f : A \to B and g : C \to D are equal when A = C and for all a \in A, f(a) = g(a) \in B\cap D.

To explain why this definition is bad, consider
##f : \mathbb{R} \to \mathbb{R}##, ##f(x) = 0##
##g : \mathbb{R} \to \{0\}##, ##g(x) = 0##.
Note that under the definition economicnerd gave these would be considered equal. However, g is a surjection while f is not.
 
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